Higher quality information

It’s 8 a.m.

I started reading feeds at 6:45 a.m.

So far this morning I’ve dug through 1,174 posts, including about 300 press releases on PR Newswire, across 891 feeds.

I’ve shared 27 of those items on my link blog.

I’ve been challenged to think different by Tim O’Reilly.
I found two new kickass videos by the Digital Ethnography crew at Kansas State.
Got 20 search engine marketing tools.
And a whole lot more.

But, back to Tim O’Reilly. He writes about how the top bloggers get more audience while everyone else goes lacking. He explains that he looks for ideas in different places than just the obvious places. That’s a great explanation of why I read so many feeds. I find so much high quality stuff in my feeds that never makes it to TechMeme or gets linked to by any other blogger.

But, back to the videos. Here’s a vision of students today from Kansas State. This class just is so cool but the kids make me so sad — it costs about $80 an hour to sit in class in a modern University. It’s amazing that kids spend so much resources just to goof off. I shouldn’t talk, though. Reading feeds isn’t exactly what I’m getting paid to do. :-)

One PR teacher I met recently told me how she’s frustrated by her students because they’d rather read up on Paris Hilton or Lindsay Lohan than apply themselves and study about something that would actually change the world. But, that does lead to certain marketing opportunities. Here the NYTimes has an article about a new celebrity TV show that’s getting big ratings.

On the other hand, what a joy a great teacher is and this Kansas class certainly has a good one.

Thanks everyone for the higher quality information.

9 thoughts on “Higher quality information

  1. I hope you found a whole lot more. Just counting the links you mention, your signal-to-noise ratio is uselessly low.

    items scanned = 1174
    items reported = 27+1+1+20+1 = 50

    s/n% = 50/1174*100% = 4.3%

  2. I hope you found a whole lot more. Just counting the links you mention, your signal-to-noise ratio is uselessly low.

    items scanned = 1174
    items reported = 27+1+1+20+1 = 50

    s/n% = 50/1174*100% = 4.3%

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